10x^2-58x+40=0

Solution for 10x^2-58x+40=0 equation:

10x^2-58x+40=0

a = 10; b = -58; c = +40;
Δ = b2-4ac
Δ = -582-4·10·40
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-42}{2*10}=\frac{16}{20}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+42}{2*10}=\frac{100}{20}
=5
$